\ A car rental company has two rental rates. Rate 1 is $72 per day plus $0.16 per mile. Rate 2 is $144 per da?

HELP ME PLS\ A car rental company has two rental rates. Rate 1 is $72 per day plus $0.16 per mile. Rate 2 is $144 per da?
First, we'll express the two rates as equations:


R1= (72/d) +(0.16/m) Rate 1 is $72 per day + $0.16 per mile.


R2=(144/d)+ (0.08/m) Rate 2 is $144 per day + $0.08 per mile.


Since you are renting for one week (7 days) and letting x = the number of miles, we can refine the equations a bit:


R1= 504+0.16x


R2=1008+0.08x


Now the question is, what value of x (number of miles) will make R2%26lt;R1 , so we need to write the inequality:


1008+0.08x %26lt; 504+0.16x


Now we solve this inequality for x. Subtract 0.08x from both sides.


1008 %26lt; 504+0.08x


Now subtract 504 from both sides.


Finally, divide both sides by 0.08


504 %26lt; 0.08x


6300 %26lt; x or x %26gt; 6300


So, you would need to drive more than 6300 miles to pay less with rate 2.


Let's check the answer by driving 6301 miles (6301 %26gt; 6300):





R[1] = 504+0.16(6301)


R[1] = 504+1008.16


R[1] = 1512.16}}}


Rate 1 would be $1512.16 for one week's rental driven 6301 miles.


R[2] = 1008+0.08(6301)


R[2] = 1008+504.08


R[2] = 1512.08





Rate 2 would be $1512.08 for one week's rental driven 6301 miles.


So you can see that if you were to drive more than 6300 miles for the week, rate 2 would cost you less than rate 1\ A car rental company has two rental rates. Rate 1 is $72 per day plus $0.16 per mile. Rate 2 is $144 per da?
You need 2 equations and for the thing tht is changing you will introduce a variable so





Rate 1 = 72 + 0.16x





notice that as miles increase price goes up so thts why i have a x with 0.16 but 72 is a constant figure tht doesnt change depeding on how much i use the car





Rate 2 = 144





Hope tht helps
.......what the questioin?
$144 per day plus $0.32 per mile